File:Shah Rukh Khan (Berlin Film Festival 2008) 4.1.jpg
Cabirka muuqaalkaan: 556 × 599 pixels. Waxyaabaha kale xalinta: 223 × 240 pixels | 445 × 480 pixels | 712 × 768 pixels | 1,130 × 1,218 pixels.
Faylka asalka ah (1,130 × 1,218 pixels, weyninka faylka : 264 KB, nuuca MIME: image/jpeg)
_4.1.jpg){kind=link}
Qoraal kooban
| Sharaxaad | Indian actor Shah Rukh Khan, arrival for press conference of "Om Shanti Om" at the Hyatt Hotel, Potsdamer Platz, Berlin |
| Taariikhda | |
| Xigasho | cropped and revised version of ipernity.com |
| Qoraa | Siebbi |
Laysinka
This file is licensed under the Creative Commons Attribution 3.0 Unported license.
- Waad fasaxantahay:
- la wadaagid – koobi gareenta, qaybinta iyo gudbinta shaqada
- to remix – in shaqada la waafajiyo
- Shuruudaha soo socda:
- Astaan – You must give appropriate credit, provide a link to the license, and indicate if changes were made. You may do so in any reasonable manner, but not in any way that suggests the licensor endorses you or your use.
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This image, which was originally posted to Ipernity, was reviewed on 20:00, 4 April 2011 (UTC) by the administrator or trusted user Adrignola, who confirmed that it was available on Ipernity under the above license on that date. |
Taariikhda faylka
Riix taariikhda/waqtiga si aad u argto faylka sida oo ahaa markiisa hore.
| Taariikhda/Waqtiga | Sawir yar | Cabirka | Isticmaale | Ka hadalka | |
|---|---|---|---|---|---|
| kan hadda | 23:18, 2 Abriil 2011 | | 1,130 × 1,218 (264 KB) | César | =={{int:filedesc}}== {{Information |Description=Indian actor Shah Rukh Khan, arrival for press conference of "Om Shanti Om" at the Hyatt Hotel, Potsdamer Platz, Berlin |Source=cropped and revised version of [http://www.ipernity.com/doc/siebbi/1499714 iper |
Faylka lagu isticmaalay
Ma jiraan bogag adeegsanaya faylkaan.
isticmaalka faylka aduunka
Wikisyada kale ee soosocda ayaa adeegsanaya faylka:
- Ku isticmaal bjn.wikiquote.org
- Ku isticmaal en.wikipedia.org
- Ku isticmaal ja.wikipedia.org
- Ku isticmaal pt.wikipedia.org
_4.1.jpg){kind=link}